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-----22,4dm3-2 mole
2CO + O2 -> 2CO2
--------x-------1 mol
x = 22,4 dm3 * 1mol / 2 mole = 11,2dm3
11,2dm3 to objętość tlenu, czyli 21% powietrza
x to objętość powietrza, czyli 100%
x = 11,2dm3 * 100% / 21% = 53,3dm3
2.
mSO3 = 32u + 3*16u = 80u
%O = 48u * 100% / 80u = 60%
60% z 2g = 1,2g