1. Ile dm^3 CO2 powstanie podczas spalenia całkowiteko 1 kg butanu.
2. Jaką objętość w warunkach normalnych zajmuje 12,04*10^23 cząsteczek amoniaku.
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1.
![2C_{4}H_{10}+13O_{2}--->8CO_{2}+10H_{2}O 2C_{4}H_{10}+13O_{2}--->8CO_{2}+10H_{2}O](https://tex.z-dn.net/?f=2C_%7B4%7DH_%7B10%7D%2B13O_%7B2%7D---%3E8CO_%7B2%7D%2B10H_%7B2%7DO)
![n=\frac{N}{N_{A}} n=\frac{N}{N_{A}}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7BN%7D%7BN_%7BA%7D%7D)
![n=\frac{12.04*10^{23}}{6.02*10^{23}}=2mol n=\frac{12.04*10^{23}}{6.02*10^{23}}=2mol](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B12.04%2A10%5E%7B23%7D%7D%7B6.02%2A10%5E%7B23%7D%7D%3D2mol)
![V=22.4\frac{dm^{3}}{mol}*2mol=44.8dm^{3} V=22.4\frac{dm^{3}}{mol}*2mol=44.8dm^{3}](https://tex.z-dn.net/?f=V%3D22.4%5Cfrac%7Bdm%5E%7B3%7D%7D%7Bmol%7D%2A2mol%3D44.8dm%5E%7B3%7D)
__________ ____________
2mol : 8mol
116g : 8*22,4dm^3
1000g : Vx=154,48 dm^3
Odp: Powstacie ok. 154.48 dm^3 CO2.
2.
Odp: Zajmuje ojbjętość 44.8 dm^3.