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a. (f o g) (x) = f{g(x)}
= 3(2x + 1) - 5
= 6x + 3 - 5
= 6x - 2
b. (f o g) (2) = 6(2) - 2
= 12 - 2
= 10
c. (g o f) (x) = g{f(x)}
= 2(3x - 5) + 1
= 6x - 10 + 1
= 6x - 9
d. (g o f) (6) = 6(6) - 9
= 36 - 9
= 27