Question

1) diketahui f (x)=ax+b dengan f (3)=7 dan f (1)=2.tentukan
a) nilai a dan b b.)bentuk fungsi c.) nilai f(0

Answer 1

F(3) = a(3) + b                          f(1) = a(1) + b
7 = 3a + b                               2   = a + b
pakai cara eliminasi
3a + b = 7
  a + b = 2 _
2a = 5
a = 2,5
3(2,5) + b = 7
7,5 +b = 7
b = -0,5

bentuk fungsi: f(x) = 2,5x -0,5
f(0) = 2,5(0) - 0,5
f(0) = 0 - 2,5
f(0) = -0,5

Answer 2

F( 3 ) =7—3a + b = 7 f( 1 ) = 2— a + b = 2 Eliminasi ————— - 2a = 5 a = 2 1/2 a + b = 2 2 1/2 + b = 2 b = - 1/2 f( x ) = ax + b f( x ) = 2 1/2x - 1/2 f(0) = 2 1=2 ( 0 ) -1/2 = -1/2