1) dengan metode determinan. x + y - z = 1 8x + 3y - 6z = 1 -4x - y + 3z = 1 nilai y yang memenuhi sistem persamaan tersebut adalah 2) himpunan penyelesaian dari sistem persamaan linear tiga variabel berikut adalah x - 2y + z = 6 3x + y - 2z = 4 7x - 6y - z = 10
DB45
1) D= 1...1...-1 8...3...-6 -4..-1...3 Det D = -1
DX= 1...1...-1 1...3...-6 1...-1...3 Det DX = -2
DY= 1...1...-1 8...1...-6 -4..1...3 Det DY = -3
DZ = 1...1...1 8...3...1 -4...-1..1 det DZ = -4
x= Dx/D = 2 y =Dy/D = 3 z =Dz/D = 4
2) D= 1..-2...1 3...1..-2 7..-6..-1 det D = -16
DX= 6...-2....1 4....1....-2 10..-6...-1 det DX = -80
D=
1...1...-1
8...3...-6
-4..-1...3
Det D = -1
DX=
1...1...-1
1...3...-6
1...-1...3
Det DX = -2
DY=
1...1...-1
8...1...-6
-4..1...3
Det DY = -3
DZ =
1...1...1
8...3...1
-4...-1..1
det DZ = -4
x= Dx/D = 2
y =Dy/D = 3
z =Dz/D = 4
2)
D=
1..-2...1
3...1..-2
7..-6..-1
det D = -16
DX=
6...-2....1
4....1....-2
10..-6...-1
det DX = -80
DY
1...6...1
3...4...-2
7..10..-1
det DY = - 48
DZ
1..-2...6
3...1...4
7..-6..10
Det DZ = -112
x = Dx/D = 5
y = Dy/D = 3
z =DZ/D = 7