Question

Ma ktos chociaz pomysl na to.? Pilnie po3ebuje.
(½a^¼ + a^¾)² - a^³/₂ (1 + a^⁻½)


(^ - potęga)

Answer 1

(½a^¼ + a^¾)² - a^³/₂ (1 + a^⁻½) =

 

 

(1/2a^(1/4))² + 2 * 1/2a^(1/4) * a^(3/4) + (a^(3/4))² - a^(3/2) - a^(3/2) * a^(-1/2) =

 

1/4a^(2 * 1/4) + a^(1/4 + 3/4) + a^(2 * 3/4) - a^(3/2) - a^(3/2 - 1/2) =

 

1/4a^(1/2) + a^1 + a^(3/2) - a^(3/2) - a^1 = 1/4a^(1/2) = 1/4 * √a = √a / 4