Question

1.
a) 4(2-3x)+10x>(albo równe) 12
b)3-10a>-2(4a+1)
c)3(x-2)-5(2x-1)>0
d)5(x-3)-8(2x+1)>-3

Answer 1

A) 4(2-3x)+10x≥12
8-12x+10≥12
-12x≥12-8-10
-12x≥-6|:-12
x≤2

b)3-10a>-2(4a+1)
3-10a>-8a-2
-10a+8a>-2-3
-2a>-5|:-2
a<2.5

c)3(x-2)-5(2x-1)>0
3x-6-10x+5>0
-7x>1|:-7
x< -(1/7)

d)5(x-3)-8(2x+1)>-3
5x-15-16x-8>-3
-11x>20|:-11
x>- (20/11)

Answer 2

A)...
8-12x+10x>(...)12
8-2x>(...)12|-8
-2x>(..)4|: (-2)
x>(...)-2
b)...
3-10a>-8a-2|-3
-10a>-8a-5|+8a
-2a>-5|: (-2)
a>2,5
c)...
3x-6-10x+5>0
-7x-1>0|+1
-7x>1|: (-7)
x> -1/7
d)...
5x-15-16x-8>-3
11x-23>-3|+23
11x?20| : 11
x> 20/11
x>1 9/20


*../... ułamek

Answer 3

a)

4(2-3x)+10x>(albo równe) 12

8-12x+10x≥12

-12x+10x≥12-8

-2x≥4

x≤-2

b)

3-10a>-2(4a+1)

3-10a>-8a-2

-10a+8a>-2-3

-2a>-5

a<2,5

c)

3(x-2)-5(2x-1)>0

3x-6-10x+5>0

3x-10x>0+6-5

-7x>1

x<-¹/₇

d)

5(x-3)-8(2x+1)>-3

5x-15-16x-8>-3

5x-16x>-3+15+8

-11x>20

x<-1⁹/₂₀