" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
mHBr=81u
16,8g (CnH2n) + xg (HBr) = 33g (CnH2n+1 Br)
x=16,2g HBr)
CnH2n + HBr------>CnH2n+1 Br
16,8g alkenu--------16,2g HBr
xg alkenu------------81g HBr
x=84g alkenu
CnHn2=84
12n+2n=84
14n=84
n=6
Szukanym alkenem jest HEKSEN--C6H12
2.
mCaC2=40u+2*12u=64u
CaC2 + 2H2O----->CH≡CH + Ca(OH)2
64g CaC2------22,4dm3 C2H2
xg CaC2--------8dm3 C2H2
x=22,8g CaC2