x2 - 6x +9 </ 0
pisac tez dokladne odpowiedzi
x2 - 6x +9 ≤ 0
Δ= b² - 4ac = (-6)² - 4*9 = 36 -36 = 0
x₁ = x₂ = -b/2a = 6/2 = 3
x² - 6x + 9 ≤ 0
(x - 3)² ≤ 0
Wyrażenie (x - 3)² jest zawsze ≥ 0
to x = 3
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x2 - 6x +9 ≤ 0
Δ= b² - 4ac = (-6)² - 4*9 = 36 -36 = 0
x₁ = x₂ = -b/2a = 6/2 = 3
x² - 6x + 9 ≤ 0
(x - 3)² ≤ 0
Wyrażenie (x - 3)² jest zawsze ≥ 0
to x = 3