Question

Rozwiąż równania:
a) y+3/1,5=1⅔/4
b) ⅔=3a-4/a+2
c) 1⅓b-4/b+2,4=3/0,75

Answer 1

a)

y+3/1,5=1⅔/4 =

y+2 = 5/3 : 4

y+2 = 3/5 * 4

y+2= 12/15

y+2=0,8  /-2

y= -1,2

b)

⅔=3a-4/a+2=  / :3

2/3 : 3 = a - (4/a :3) + 2/3

3/2 *3 = a - (a/4 *3 ) + 2/3

9/2 = a - 3a/4 +2/3  / *4

36/2 = 4a - 12a/4 + 8/3

18 = 4a - 3a + 8/3

18 = a + 8/3   / -8/3

18 - 8/3 = a

15 ⅓ = a

a= 15 ⅓

c)

1⅓b-4/b+2,4=3/0,75 

1⅓b- 4/b +2,4 = 4

1⅓b-4b + 2,4=4

-4⅔b +2,4 = 4 / -2,4

-4⅔b = 1,6    

-14/3 b = 1 i 6/10  /: -14/3

-b = 1 i 6/10 : -14/3 

-b = 1 i 6/10 * -3/14

-b = - 48/140

b= 48/140