Oblicz opór włókna żarówki o parametrach 4,5 V/ 0,3A
R = U/I = 4,5V/0,3A = 15 Ω (omów)
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U = 4,5 V
I = 0,3 A
Wiec
R = 4,5:0,3 = 15 [omow to jest omega grecka]
R = U/I = 4,5V/0,3A = 15 Ω (omów)