Przedstaw iloraz w postaci potęgi o wykładniku ujemnym. (-0,1)^3*(-0,1)^5*(-0,1)/(-0,1)^3*(-0,1)^-6
(-0,1)^3 *(-0,1)^5 *(-0,1)/(-0,1)^3 *(-0,1)^-6 =
= (-0,1)^9/(-0,1)^-3 =
= (-0,1)^12 =
= (-1/10)^12 =
= (-10)^-12
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(-0,1)^3 *(-0,1)^5 *(-0,1)/(-0,1)^3 *(-0,1)^-6 =
= (-0,1)^9/(-0,1)^-3 =
= (-0,1)^12 =
= (-1/10)^12 =
= (-10)^-12
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