zrodlo ciepla w silniku CORTNOTA ma teperature 600`C temperatura chlodnicy wynosi 200 `C oblicz sprawnosc silnika.
Prosze o pomoc ; ))
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η - sprawność
T₁=600C=873K
T₂=200C=473K
η=(T₁-T₂)/T₁=400/873≈45%