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................. x%
70g 50% ............. x-10
50/70 = 50-x/x-10
50(x-10) = 70(50-x)
50x-500 = 3500-70x
120x = 4000
x = 33,33%
45g wody i 5g sub
50% z 70g to 35g
35g wody i 35g sub
Razem (po dodaniu): 80g wody i 40g substancji
80g + 40g = 120g
40g z 120g to 1/3 = 33,(3)%
Odp: Stężenie wyniesie 33,(3)%.