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M Fe=56g/mol
n=0,83mola
m=M*n
m=56*0,83
m = 46,48g Fe
FexBry
mFe=56u (x)
mBr=80u (y)
56x/80y = 46,5/200
11200x = 3720y
3x = y
x : y = 1 : 3
Powstał FeBr₃