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masa substancji - 20g (bo Cp=20%)
masa rozpuszczalnika = 100-20=80(g)
100-80=20(g)
Odp: Masa cukru po odparowaniu wynosi 20g.
mr=100g
Cp=20%
ms=Cp*mr/100%
ms=20*100/100
ms=20g cukru