Cx H2x
12x + 2x * 1=70
14x=70
x=5
1. niecałkowite spalanie
2C5 H10 +5O2= 10C + 10H2O
C5 H10 + 5O2 = 5CO +5 H2O
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Cx H2x
12x + 2x * 1=70
14x=70
x=5
1. niecałkowite spalanie
2C5 H10 +5O2= 10C + 10H2O
C5 H10 + 5O2 = 5CO +5 H2O