Odpowiedź:
a ) [tex]\frac{1}{2} x^{2} = 9 / * 2\\x^{2} = 9*2\\x = -\sqrt{9*2} = - 3\sqrt{2}[/tex] lub [tex]x = \sqrt{9*2} = 3\sqrt{2}[/tex]
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b) 2 [tex]x^{2} - 1 = 17[/tex]
[tex]2x^{2} = 18 / : 2\\x^{2} = 9\\x = - 3[/tex]lub x = 3
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c )
12 - 3 x² = 0 /: 3
4 - x² = 0
x² = 4
x = - 2 lub x = 2
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d )
6 x² = 8 - x² / + x²
7 x² = 8 / : 7
x² = [tex]\frac{8}{7} = \frac{4*2}{7}[/tex]
x = - [tex]\sqrt{\frac{4*2}{7} } = - \frac{2\sqrt{2} }{\sqrt{7} } = - \frac{2\sqrt{14} }{7}[/tex] lub x = [tex]\sqrt{\frac{4*2}{7} } = \frac{2\sqrt{14} }{7}[/tex]
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e )
4*(x² + 2 ) = 8 / : 4
x² + 2 = 2
x² = 2 - 2 = 0
x = 0
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f ) [tex]\frac{5 + x^2}{2} - 4 = 0 / * 2\\5 + x^{2} - 8 = 0\\x^{2} - 3 = 0\\x^{2} = 3\\x = - \sqrt{3}[/tex]lub [tex]x = \sqrt{3}[/tex]
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Odpowiedź:
a ) [tex]\frac{1}{2} x^{2} = 9 / * 2\\x^{2} = 9*2\\x = -\sqrt{9*2} = - 3\sqrt{2}[/tex] lub [tex]x = \sqrt{9*2} = 3\sqrt{2}[/tex]
================================================
b) 2 [tex]x^{2} - 1 = 17[/tex]
[tex]2x^{2} = 18 / : 2\\x^{2} = 9\\x = - 3[/tex]lub x = 3
=========================
c )
12 - 3 x² = 0 /: 3
4 - x² = 0
x² = 4
x = - 2 lub x = 2
===================
d )
6 x² = 8 - x² / + x²
7 x² = 8 / : 7
x² = [tex]\frac{8}{7} = \frac{4*2}{7}[/tex]
x = - [tex]\sqrt{\frac{4*2}{7} } = - \frac{2\sqrt{2} }{\sqrt{7} } = - \frac{2\sqrt{14} }{7}[/tex] lub x = [tex]\sqrt{\frac{4*2}{7} } = \frac{2\sqrt{14} }{7}[/tex]
====================================================
e )
4*(x² + 2 ) = 8 / : 4
x² + 2 = 2
x² = 2 - 2 = 0
x = 0
=======
f ) [tex]\frac{5 + x^2}{2} - 4 = 0 / * 2\\5 + x^{2} - 8 = 0\\x^{2} - 3 = 0\\x^{2} = 3\\x = - \sqrt{3}[/tex]lub [tex]x = \sqrt{3}[/tex]
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Szczegółowe wyjaśnienie: