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F=k*q1*q2/r²
F1=k*3q1*4q2/r²=12*k*q1*q2/r²=12*10mN=120mN
ładunki przyjmuje 1 dla kazdego
0,01N = 2/r2
0,01 * r2 = 2
r2 = 200
r = 14,14
(3 + 4 ) / 14,14 = 0,5 N bedzie wynosic ta siła