mCa(OH)2=40u+2*16u+2*1u=74 u
Stosunek masowy:
mCa:mO:mH=40:32:2=20:16:1
Zawartość procentowa wapnia:
40u---x%
74u---100%
x=54,05%
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mCa(OH)2=40u+2*16u+2*1u=74 u
Stosunek masowy:
mCa:mO:mH=40:32:2=20:16:1
Zawartość procentowa wapnia:
40u---x%
74u---100%
x=54,05%