Odpowiedź:
Szczegółowe wyjaśnienie:
a) NIE
[tex]\left \{ {{2x + y = 1} \atop {x - 3y = -7}} \right\\\\\left \{ {{2(2) + (-3) = 1} \atop {2 - 3(-3) = -7}} \right\\\\\left \{ {{4 - 3 = 1} \atop {2 + 9 = -7}} \right\\\\\left \{ {{1= 1} \atop {11 = -7}} \right\\\\\left \{ {{L = P} \atop {L \neq P}} \right. \\\\[/tex]
b) NIE
[tex]\left \{ {{5x -y=7} \atop {-x -y=1}} \right\\\\\left \{ {{5(2) -(-3)=7} \atop {-2 -(-3)=1}} \right\\\\\left \{ {{10 + 3 = 7} \atop {-2 + 3 = 1}} \right\\\\\left \{ {{13 = 7} \atop {1 = 1}} \right\\\\\left \{ {L \neq P} \atop {L = P}} \right\\\\[/tex]
c) NIE
[tex]\left \{ {{2x - 3y = 0} \atop {3x - 2y = 0}} \right.\\\\\left \{ {{2(2) - 3(-3) = 0} \atop {3(2) - 2(-3) = 0}} \right. \\\\\left \{ {{4 + 9 = 0} \atop {6 + 6 = 0}} \right. \\\\\left \{ {{13 = 0} \atop {12 = 0}} \right. \\\\\left \{ {{L \neq P} \atop {L \neq P}} \right. \\\\[/tex]
d) TAK
[tex]\left \{ {{5x + 4y = -2} \atop {-4x -5y = 7}} \right. \\\\\left \{ {{5(2) + 4(-3) = -2} \atop {-4(2) -5(-3) = 7}} \right. \\\\\left \{ {{10 - 12 = -2} \atop {-8 + 15 = 7}} \right. \\\\\left \{ {{-2 = -2} \atop {7 = 7}} \right. \\\\\left \{ {{L = P} \atop {L = P}} \right. \\\\[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Odpowiedź:
Szczegółowe wyjaśnienie:
a) NIE
[tex]\left \{ {{2x + y = 1} \atop {x - 3y = -7}} \right\\\\\left \{ {{2(2) + (-3) = 1} \atop {2 - 3(-3) = -7}} \right\\\\\left \{ {{4 - 3 = 1} \atop {2 + 9 = -7}} \right\\\\\left \{ {{1= 1} \atop {11 = -7}} \right\\\\\left \{ {{L = P} \atop {L \neq P}} \right. \\\\[/tex]
b) NIE
[tex]\left \{ {{5x -y=7} \atop {-x -y=1}} \right\\\\\left \{ {{5(2) -(-3)=7} \atop {-2 -(-3)=1}} \right\\\\\left \{ {{10 + 3 = 7} \atop {-2 + 3 = 1}} \right\\\\\left \{ {{13 = 7} \atop {1 = 1}} \right\\\\\left \{ {L \neq P} \atop {L = P}} \right\\\\[/tex]
c) NIE
[tex]\left \{ {{2x - 3y = 0} \atop {3x - 2y = 0}} \right.\\\\\left \{ {{2(2) - 3(-3) = 0} \atop {3(2) - 2(-3) = 0}} \right. \\\\\left \{ {{4 + 9 = 0} \atop {6 + 6 = 0}} \right. \\\\\left \{ {{13 = 0} \atop {12 = 0}} \right. \\\\\left \{ {{L \neq P} \atop {L \neq P}} \right. \\\\[/tex]
d) TAK
[tex]\left \{ {{5x + 4y = -2} \atop {-4x -5y = 7}} \right. \\\\\left \{ {{5(2) + 4(-3) = -2} \atop {-4(2) -5(-3) = 7}} \right. \\\\\left \{ {{10 - 12 = -2} \atop {-8 + 15 = 7}} \right. \\\\\left \{ {{-2 = -2} \atop {7 = 7}} \right. \\\\\left \{ {{L = P} \atop {L = P}} \right. \\\\[/tex]