Odpowiedź:
a) 6√7 - 3√7 = 3√7
b) [tex]\sqrt{39} *\sqrt{\frac{13}{3} } = \sqrt{13}*\sqrt{3} *\frac{\sqrt{13} }{\sqrt{3} } = (\sqrt{13} )^2 = 13[/tex]
c) [tex]\sqrt{500} + 4\sqrt{5} = \sqrt{100*5} + 4\sqrt{5} = 10\sqrt{5} + 4\sqrt{5} = 14\sqrt{5}[/tex]
d ) [tex]3\sqrt{21} *\frac{1}{7} \sqrt{7} = 3*\sqrt{3} *\sqrt{7} *\frac{1}{7}*\sqrt{7} = 3\sqrt{3}[/tex]
e ) ( [tex]\frac{3\sqrt{15} }{5} )^2 = \frac{9*15}{25} = \frac{27}{5} = 5\frac{2}{5}[/tex]
Szczegółowe wyjaśnienie:
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Verified answer
Odpowiedź:
a) 6√7 - 3√7 = 3√7
b) [tex]\sqrt{39} *\sqrt{\frac{13}{3} } = \sqrt{13}*\sqrt{3} *\frac{\sqrt{13} }{\sqrt{3} } = (\sqrt{13} )^2 = 13[/tex]
c) [tex]\sqrt{500} + 4\sqrt{5} = \sqrt{100*5} + 4\sqrt{5} = 10\sqrt{5} + 4\sqrt{5} = 14\sqrt{5}[/tex]
d ) [tex]3\sqrt{21} *\frac{1}{7} \sqrt{7} = 3*\sqrt{3} *\sqrt{7} *\frac{1}{7}*\sqrt{7} = 3\sqrt{3}[/tex]
e ) ( [tex]\frac{3\sqrt{15} }{5} )^2 = \frac{9*15}{25} = \frac{27}{5} = 5\frac{2}{5}[/tex]
Szczegółowe wyjaśnienie: