Odpowiedź:
[tex]\displaystyle \frac{(x^{2} -9)(2x+4)}{2x-6} =0\quad\frac{2(x-3)(x+3)(x+2)}{2(x-3)} =0\quad D=R-\{3\}\\ x_1=3\notin D\quad x_2=-3\quad x_3=-2\\x_2+x_3=-3-2=-5[/tex]
C
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Odpowiedź:
[tex]\displaystyle \frac{(x^{2} -9)(2x+4)}{2x-6} =0\quad\frac{2(x-3)(x+3)(x+2)}{2(x-3)} =0\quad D=R-\{3\}\\ x_1=3\notin D\quad x_2=-3\quad x_3=-2\\x_2+x_3=-3-2=-5[/tex]
C