e)
[tex]\frac{3x-5}{2} - \frac{5x-1}{10}=0 \ \ \ |\cdot10\\\\10\cdot\frac{3x-5}{2}-10\cdot\frac{5x-1}{10} = 0\\\\5(3x-5)-(5x-1) = 0\\\\15x -25 -5x+1 = 0\\\\10x -24 = 0\\\\10x = 24 \ \ \ |:10\\\\\boxed{x = 2\frac{2}{5}}[/tex]
f)
[tex]\frac{x}{2}=\frac{2}{5}(4-x)-4 \ \ \ |\cdot10\\\\5x=4(4-x)-40\\\\5x=16-4x-40\\\\5x+4x=-40-16\\\\9x = -56 \ \ \ |:9\\\\\boxed{x = -6\frac{2}{9}}[/tex]
g)
[tex]\frac{2x-1}{5}-\frac{x-2}{2} = 0,7x \ \ \ |\cdot10\\\\2(2x-1)-5(x-2) = 7x\\\\4x-2-5x+10 = 7x\\\\-x-7x+8 = 0\\\\-8x = -8 \ \ \ |:(-8)\\\\\boxed{x = 1}[/tex]
h)
[tex]2x-\frac{3x+5}{4}=-\frac{1}{4}x -1 \ \ \ |\cdot4\\\\8x-(3x+5) = -x-4\\\\8x-3x-5 = -x-4\\\\5x+x = -4+5\\\\6x=1 \ \ \ |:6\\\\x =\boxed{ \frac{1}{6}}[/tex]
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Verified answer
e)
[tex]\frac{3x-5}{2} - \frac{5x-1}{10}=0 \ \ \ |\cdot10\\\\10\cdot\frac{3x-5}{2}-10\cdot\frac{5x-1}{10} = 0\\\\5(3x-5)-(5x-1) = 0\\\\15x -25 -5x+1 = 0\\\\10x -24 = 0\\\\10x = 24 \ \ \ |:10\\\\\boxed{x = 2\frac{2}{5}}[/tex]
f)
[tex]\frac{x}{2}=\frac{2}{5}(4-x)-4 \ \ \ |\cdot10\\\\5x=4(4-x)-40\\\\5x=16-4x-40\\\\5x+4x=-40-16\\\\9x = -56 \ \ \ |:9\\\\\boxed{x = -6\frac{2}{9}}[/tex]
g)
[tex]\frac{2x-1}{5}-\frac{x-2}{2} = 0,7x \ \ \ |\cdot10\\\\2(2x-1)-5(x-2) = 7x\\\\4x-2-5x+10 = 7x\\\\-x-7x+8 = 0\\\\-8x = -8 \ \ \ |:(-8)\\\\\boxed{x = 1}[/tex]
h)
[tex]2x-\frac{3x+5}{4}=-\frac{1}{4}x -1 \ \ \ |\cdot4\\\\8x-(3x+5) = -x-4\\\\8x-3x-5 = -x-4\\\\5x+x = -4+5\\\\6x=1 \ \ \ |:6\\\\x =\boxed{ \frac{1}{6}}[/tex]