[tex]7a)\\\\\frac{2-4\sqrt{3}}{2}=\frac{\not{2}^1(1-2\sqrt{3})}{\not{2}^1}=1-2\sqrt{3}\\\\b)\\\\\frac{6+12\sqrt{2}}{3}=\frac{ \not{6}^2(1+2\sqrt{2})}{\not{3}^1}=2(1+2\sqrt{2)}[/tex]
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[tex]7a)\\\\\frac{2-4\sqrt{3}}{2}=\frac{\not{2}^1(1-2\sqrt{3})}{\not{2}^1}=1-2\sqrt{3}\\\\b)\\\\\frac{6+12\sqrt{2}}{3}=\frac{ \not{6}^2(1+2\sqrt{2})}{\not{3}^1}=2(1+2\sqrt{2)}[/tex]