[tex]4\frac{13}{9}=\frac{4\cdot9+13}{9}=\frac{36+13}{9}=\frac{49}{9}\\\\\sqrt{\frac{49}{9}}=\frac{\sqrt{49}}{\sqrt{9}}=\boxed{\frac{7}{3}=2\frac{1}{3}}[/tex]
Odpowiedź B.
[tex]\sqrt{4\dfrac{13}{9}}=\sqrt{\dfrac{49}{9}}=\dfrac{7}{3}=2\dfrac{1}{3}[/tex]
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[tex]4\frac{13}{9}=\frac{4\cdot9+13}{9}=\frac{36+13}{9}=\frac{49}{9}\\\\\sqrt{\frac{49}{9}}=\frac{\sqrt{49}}{\sqrt{9}}=\boxed{\frac{7}{3}=2\frac{1}{3}}[/tex]
Odpowiedź B.
[tex]\sqrt{4\dfrac{13}{9}}=\sqrt{\dfrac{49}{9}}=\dfrac{7}{3}=2\dfrac{1}{3}[/tex]