Zadanie 1
a) mCO2=12u+2*16u
Stosunek masowy:
mC:mO=12:32=3:8
b) mCO=12u+16u
mC:mO=12:16=3:4
c) mFe2S3=2*56u+3*32u
mFe:mS=112:96=7:6
Zadanie 2
a) mCuO=64u+16u=80u
64u---x%
80u---100%
x=80%Cu
100%-80%=20%O
b) mAg2O=2*108u+16u=232u
216u---x%
232u---100%
x=93,1%Ag
100%-93,1%=6,9%O
c) mCaC2=40u+2*12u=64u
40u---x%
64u---100%
x=62,5%Ca
100%-62,5%=37,5%C
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Zadanie 1
a) mCO2=12u+2*16u
Stosunek masowy:
mC:mO=12:32=3:8
b) mCO=12u+16u
Stosunek masowy:
mC:mO=12:16=3:4
c) mFe2S3=2*56u+3*32u
Stosunek masowy:
mFe:mS=112:96=7:6
Zadanie 2
a) mCuO=64u+16u=80u
64u---x%
80u---100%
x=80%Cu
100%-80%=20%O
b) mAg2O=2*108u+16u=232u
216u---x%
232u---100%
x=93,1%Ag
100%-93,1%=6,9%O
c) mCaC2=40u+2*12u=64u
40u---x%
64u---100%
x=62,5%Ca
100%-62,5%=37,5%C