Odpowiedź:
α=180-67,5-67,5=45°
[tex]\displaystyle P=\frac{1}{2} \cdot 20\cdot20\sin45=200\cdot\frac{\sqrt{2} }{2} =100\sqrt{2}[/tex]
D
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Odpowiedź:
α=180-67,5-67,5=45°
[tex]\displaystyle P=\frac{1}{2} \cdot 20\cdot20\sin45=200\cdot\frac{\sqrt{2} }{2} =100\sqrt{2}[/tex]
D