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R=U/J
J=U/R
J=9/25A=0,36A
2
R1=8OM
R2= 2OM
R3= 5OM
Ra=8oM+2OM
Ra=10 OM
1/Rc= 1/Ra + 1 / R3
1/Rc=1/10+1/5
1/Rc=1/10+2/10
1/Rc=3/10
3Rc=10
Rc=10/3
Rc=3 i jedna trzecia OM :)
R=25Ω
U=9V
I=?
P=?
------------------------------------------------
I=U/R=9V/25Ω=0,36A
P=U*I=9V*0,36A=3,24W
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2)
R1=8Ω
R2=2Ω
R3=5Ω
Rz=?
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R1 i R2 połączone szeregowo
Rz1=R1+R2=8Ω+2Ω=10Ω
Rz1 i R3 połączone równolegle
Rz=Rz1*R3/(Rz1+R3)=10*5/(10+5)=3,33Ω