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a. 3 mole Pb = 3 ×207 = 621 g
b. 2 mole HNO₃ = 2 ( 1 +14+ (3×16))= 126 g
zad 2. HNO₃ - 63 g - 1 mol
6,3g - x
x= 6,3 ÷ 63
x = 0,1 mola