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n(Ca)= 20/40=0,5 mol
n(O2)=0,5/2=0,25 mol
V(O2)=0,25*44.8=11.2 dm3
4NH3+3O2=2N2+6H2O
n(O2)=224/22.4=10 moli
4 mol NH3 ----3 molO2
x mol-----------10 mol O2
x=13,33 mol NH3