1.
CH3OH + HCl ----> CH3Cl + H2O
32g metanolu ---- 50,5g chlork metylu
100g metanolu --- X
X=158g CH3Cl
158g --- 100%
X --- 70%
X=110,6g CH3Cl
2.
Cm=n/V
n= 0,1 x 0,2
n=0,02mola
68g C2H5ONa--- 1 mol
X --- 0,02 mola
X= 1,36g C2H5ONa
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
1.
CH3OH + HCl ----> CH3Cl + H2O
32g metanolu ---- 50,5g chlork metylu
100g metanolu --- X
X=158g CH3Cl
158g --- 100%
X --- 70%
X=110,6g CH3Cl
2.
Cm=n/V
n= 0,1 x 0,2
n=0,02mola
68g C2H5ONa--- 1 mol
X --- 0,02 mola
X= 1,36g C2H5ONa