Question

Zad1. Do 40g, 20% roztworu kwasu siarkowego 6 dodano 10g wody oblicz nowe Cp roztworu


zad2. Zmieszano ze sobą 150g, 20% roztworu i 250g, 10% roztworu oblicz nowe Cp zmieszanych roztworów

PROSZE SZYBKO NA JUTRO POTRZEBUJE !!!!

Answer 1

Zadanie 1
mr = 40g
cp = 20%

ms = mr*cp/100%

ms = 40g*20%/100% = 8g

mr2 = 40g+10g = 50g
ms = 8g

cp = ms/mr * 100%

cp = 8g/50g * 100% = 16%

zadanie 2
mr1 = 150g
cp1 = 20%

ms1 = 150g*20%/100% = 30g

mr2 = 250g
cp2 = 10%

ms2 = 250g*10%/100% = 25g

mr3 = 150g+250g = 400g
ms3 = 25g+30g = 55g

cp3 = 55g/400g * 100% = 13,75%