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H2SO3
mH-2u
mS=32u
m0=48u
razem=82u
%mS= 32/82 *100%
%mO=48/82*100%
stosunek masowy: H:S:0 jak 1:16:24
tlenek siarki IV- SO2
mS=32u
mO=32u
stosunek S:O jak 32:32 czyli 1:1