Odpowiedź:
moge naj? <3
a) 2Li + 2H₂O → 2LiOH + H₂↑
b) BaO + H₂O → Ba(OH)₂
c) SrO + H₂O → Sr(OH)₂
d) SnBr₂ + 2KOH → Sn(OH)₂ ↓ + 2KBr
e)NiI₂ + 2NaOH → Ni(OH)₂↓ + 2NaI
f) BiCl₃ + NaOH → Bi(OH)₃ + NaCl
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Odpowiedź:
moge naj? <3
a) 2Li + 2H₂O → 2LiOH + H₂↑
b) BaO + H₂O → Ba(OH)₂
c) SrO + H₂O → Sr(OH)₂
d) SnBr₂ + 2KOH → Sn(OH)₂ ↓ + 2KBr
e)NiI₂ + 2NaOH → Ni(OH)₂↓ + 2NaI
f) BiCl₃ + NaOH → Bi(OH)₃ + NaCl