Odpowiedź:
m=0,5kg
t1=25
Q=195000J
cw=130J/kgC
Q=cw*m*ΔT
ΔT=Q/cw*m
ΔT=195000J/0,5kg*130J/kgC
ΔT=3000°C
t2=ΔT+t1
t2=3025°C
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Odpowiedź:
m=0,5kg
t1=25
Q=195000J
cw=130J/kgC
Q=cw*m*ΔT
ΔT=Q/cw*m
ΔT=195000J/0,5kg*130J/kgC
ΔT=3000°C
t2=ΔT+t1
t2=3025°C