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Cp=ms/mr x 100%
0,2=ms/400
ms=80g soli
400-80=320g wody
2.
wzór: KOH
masa cz: 39 + 16 + 1= 56g
1 mol - 56g
X moli - 28g
X=0,5 mola KOH
Cm=n/V
Cm=0,5/0,4dm3
Cm=1,25 mol/dm3
mh₂o=400-80=320g
2.V=400cm³=0,4dm³
mkoh=28g
Mkoh=39+17=56
n=m/M
n=28/56=0,5mola
Cm=n/v
Cm=0,5/0,4=1,25M