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36g wody= 4 g wodoru
7,2=x
x=0,8
0,8 = x dm3
4= 44,8
x=8,96 dm3 wodoru
2H20 ----> 2H2 + 02
7.2g.........x.....4.48dm^3
36g - 44.8dm^3
7.2g - x
x=7.2x44.8/36=8.96dm^3 wodoru
Odp Wydzieli sie 8.96dm^3 wodoru
36g H2O.......44,8dm3 H2
7.2g H2O........xdm3 H2
x=8,96dm3 H2