z jaka predkoscia nalezy rzucic ciało pionowo do gory , aby uzyskało wysokosc 50m? oblicz czas trwania tego ruchu
zasada zachowania energii
v = √2gh
h = 50m
v = √2 x 10m/s² x 50m = √1000m²/s² = 31,62m/s
s = vt/2 więc t = 2s/v
t = 2 x 50m / 31,62m/s = 3,16s
W razie pytań pisz
I hope I helped
Pozdrawiam Marco12 ;)
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zasada zachowania energii
v = √2gh
h = 50m
v = √2 x 10m/s² x 50m = √1000m²/s² = 31,62m/s
s = vt/2 więc t = 2s/v
t = 2 x 50m / 31,62m/s = 3,16s
W razie pytań pisz
I hope I helped
Pozdrawiam Marco12 ;)