Z jaką szybkością musiałby poruszać się pręt aby jego długość zmalała 2 razy?
L`=L(1-u^2/c^2)^(1/2)
1/2=(1-u^2/c^2)^(1/2)
1/4=1-u^2/c^2
u^2/c^2=3/4
4u^2=3c^2
u^2=3/4c^2
u^2=3/4*90000000000km/s
u= 259807 km/s
u=[3^(1/2)/2]c
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
L`=L(1-u^2/c^2)^(1/2)
1/2=(1-u^2/c^2)^(1/2)
1/4=1-u^2/c^2
u^2/c^2=3/4
4u^2=3c^2
u^2=3/4c^2
u^2=3/4*90000000000km/s
u= 259807 km/s
u=[3^(1/2)/2]c