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Jawabnnya di atas.maaf aku gk bisa yang nomer 2,cuma bisa nomer 1
semoga membantu
1.]
x/2 + y/4 = 6 [x 4]
2x + y = 24 ... (i)
y/6 - z/2 = -2 [x 6]
y - 3z = -12 ... (ii)
z/4 + x/3 = 4 [x 12]
4x + 3z = 48 ... (iii)
Eliminasi (i) dan (ii)
2x + y = 24
y - 3z = -12
_________ [–]
2x + 3z = 36 ... (iv)
Eliminasi (iii) dan (iv)
4x + 3z = 48
2x + 3z = 36
__________ [–]
2x = 12
x = 6
2(6) + 3z = 36
3z = 24
z = 8
y - 3(8) = -12
y = -12 + 24
y = 12
HP : {(6 , 12 , 8})
2.]
Misal 1/x = a , 1/y = b , 1/z = c
a + 2b + 4c = 1 => a = 1 - 2b - 4c ... (i)
-a + 4b + 12c = 0
4b + 12c = a ... (ii)
Maka :
4b + 12c = 1 - 2b - 4c
6b + 16c = 1 [x 16]
96b + 256c = 16 ... (iii)
2a + 8b + 4c = -1
2(4b + 12c) + 8b + 4c = -1
16b + 28c = -1 [x 6]
96b + 168c = -6 ... (iv)
Eliminasi (iii) dan (iv)
96b + 256c = 16
96b + 168c = -6
__________ [–]
88c = 22
c = ¼
1/z = ¼
z = 4
6b + 16(¼) = 1
6b = 1 - 4
6b = -3
b = - ½
1/y = - ½
y = -2
a = 1 - 2(-½) - 4(¼)
a = 1 + 1 - 1
a = 1
1/x = 1
x = 1
HP : {(1 , -2 , 4)}