Question

yang tau kak.... fungsi​

Answer 1

Penjelasan dengan langkah-langkah:

a) –x² + 2x – 6 = 0

a = –1, b = 2 , c = –6

x1,2 = –b ± √(b² – 4ac)

2a

x1,2 = –2 ± √(2² – 4[1][–6])

2[–1]

x1,2 = –2 ± √(4 + 24)

–2

x1,2 = –2 ± 2√7

–2

x1,2 = –1 ± √7

x1 = –1 + √7

x2 = –1 – √7

b) –2x² – 9x + 5 = 0

–(2x² + 9x – 5) = 0

–(2x – 1)(x + 5) = 0

(1 – 2x)(5 + x) = 0

x1 = ½

x1 = ½x2 = –5

c) 2x² + 7x – 5 = 0

a = 2 , b = 7 , c = –5

x1,2 = –b ± √(b² – 4ac)

2a

x1,2 = –7 ± √(7² – 4[2][-5])

2[2]

x1,2 = –7 ± √(49 + 40)

4

x1,2 = –7 ± √89

4

x1 = ¼(–7 + √89)

x2 = –¼(7 + √89)