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2) -5 < 2x - 7 ≤ 3 --> ketiga ruas ditambah 7
-5 + 7 < 2x - 7 + 7 ≤ 3 + 7
2 < 2x ≤ 10 ---> ketiga ruas dibagi 2
1 < x ≤ 5
3) x - 6 < 4
x < 4 + 6
x < 10
4) 3x - 3 ≤ 4x - 7
3x - 4x ≤ -7 + 3
-x ≤ -4
x ≥ 4
5) 4x + 2 < 6x - 7
4x - 6x < -7 - 2
-2x < -9
x > 9/2
semoga membantu ya :)