Question

Yang jago mtk tolong dong dibantu

Answer 1

∫ x/(x²+3x-4) dx
= ∫ ((x+4)-4)/(x+4)(x-1) dx
= ∫ ((x+4)/(x+4)(x-1) dx - ∫ 4/(x+4)(x-1) dx
= ∫ 1/(x-1) dx - ∫ 4/(x+4)(x-1) dx
= ln (x-1) - ∫ 4/(x+4)(x-1) dx
= ln (x-1) - (4/5)(ln (x-1) - ln (x+4)
= (1/5)(ln (x-1) + 4.ln (x+4))