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L selimut=2phi.r.t
Ls/2phi.t=r
2200/2*3,14*25=r
14=r
Luas permukaan =Luas selimut + 2Luas alas
Lp=2200+2*22/7*14*14
Lp=2200+1232
Lp=3432 cm2
L selimut = 2.200 cm²
tinggi = 25 cm
Tanya: Luas permukaan ...?
Jawab:
L selimut = 2πrt
2.200 = 2π r (25)
r = 14 cm
Luas permukaan = 2πr (r + t)
Luas permukaan = 2π(14) (14+25) = 3.432 cm² (a)