Jawaban:
(1). Luas alas, Luas tutup = 2 × p × l = 2 × 21 cm × 6 cm = 252 cm²
(2). Luas bidang depan belakang = 2 × p × t = 2 × 21 cm × 5 cm = 210 cm²
(3). Luas bidang samping = 2 × l × t = 2 × 6 cm × 5 cm = 60 cm²
Luas permukaan balok = jumlah ke-6 bidang = 2 × (p × l + p × t + l × t) = 2 × (252 cm² + 210 cm² + 60 cm²) = 2 × 522 cm² = 1044 cm²
Volume balok = p × l × t = 21 cm × 6 cm × 5 cm = 630 cm³
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Verified answer
Jawaban:
(1). Luas alas, Luas tutup = 2 × p × l = 2 × 21 cm × 6 cm = 252 cm²
(2). Luas bidang depan belakang = 2 × p × t = 2 × 21 cm × 5 cm = 210 cm²
(3). Luas bidang samping = 2 × l × t = 2 × 6 cm × 5 cm = 60 cm²
Luas permukaan balok = jumlah ke-6 bidang = 2 × (p × l + p × t + l × t) = 2 × (252 cm² + 210 cm² + 60 cm²) = 2 × 522 cm² = 1044 cm²
Volume balok = p × l × t = 21 cm × 6 cm × 5 cm = 630 cm³