Yang bisa tolong bantu ya,
tentukan nilai x dari 2^3x+1 = 3 akar 64^x+1
ket : ^ = pangkat
tentukan nilai x dari 2^3x+1 = 3 akar 64^x+1
ket : ^ = pangkat
MicoArrafi
![$\begin{align} 2^{3x+1}&=\sqrt[3]{64^{x+1}}\\2^{3x+1}&=\sqrt[3]{4^{3(x+1)}}\\2^{3x+1}&=4^{x+1}\\2^{3x+1}&=2^{2(x+1)}\\2^{3x+1}&=2^{2x+2}\\3x+1&=2x+2\\3x-2x&=2-1\\x&=\bold1 \end](https://tex.z-dn.net/?f=%24%5Cbegin%7Balign%7D+2%5E%7B3x%2B1%7D%26%3D%5Csqrt%5B3%5D%7B64%5E%7Bx%2B1%7D%7D%5C%5C2%5E%7B3x%2B1%7D%26%3D%5Csqrt%5B3%5D%7B4%5E%7B3%28x%2B1%29%7D%7D%5C%5C2%5E%7B3x%2B1%7D%26%3D4%5E%7Bx%2B1%7D%5C%5C2%5E%7B3x%2B1%7D%26%3D2%5E%7B2%28x%2B1%29%7D%5C%5C2%5E%7B3x%2B1%7D%26%3D2%5E%7B2x%2B2%7D%5C%5C3x%2B1%26%3D2x%2B2%5C%5C3x-2x%26%3D2-1%5C%5Cx%26%3D%5Cbold1+%5Cend "$\begin{align} 2^{3x+1}&=\sqrt[3]{64^{x+1}}\\2^{3x+1}&=\sqrt[3]{4^{3(x+1)}}\\2^{3x+1}&=4^{x+1}\\2^{3x+1}&=2^{2(x+1)}\\2^{3x+1}&=2^{2x+2}\\3x+1&=2x+2\\3x-2x&=2-1\\x&=\bold1 \end")
2 votes
Thanks 0
diansari183
makasih :)