Jawab:
Penjelasan dengan langkah-langkah:
2. a. f(x) = 2x + 3
f'(x) = 2
b. f(x) = x² - 3x - 4
f'(x) = 2x - 3
c. f(x) =
f'(x) = 6 x (4x + 1)^-1
f'(x) = 6 x -1 x (4x + 1)^-2
f'(x) = -6 x (4x + 1)^-2
f'(x) = }[/tex]
f'(x) = - }[/tex]
f'(x) = - + 8x +1} }[/tex]
d. f(x) =
= (4x - 5)^1/2
= (4x - 5)^1/2 x 4
= (4x - 5)^-1/2 x 2
= 2(4x - 5)^-1/2
=
= }[/tex]
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Jawab:
Penjelasan dengan langkah-langkah:
2. a. f(x) = 2x + 3
f'(x) = 2
b. f(x) = x² - 3x - 4
f'(x) = 2x - 3
c. f(x) =
f'(x) = 6 x (4x + 1)^-1
f'(x) = 6 x -1 x (4x + 1)^-2
f'(x) = -6 x (4x + 1)^-2
f'(x) =^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B-6%7D%7B%5Btex%5D%284x%20%2B%201%29%5E%7B2%7D "\frac{-6}{[tex](4x + 1)^{2}")
}[/tex]
f'(x) = -^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B%5Btex%5D%284x%20%2B%201%29%5E%7B2%7D "\frac{6}{[tex](4x + 1)^{2}")
}[/tex]
f'(x) = -![\frac{6}{(16[tex]x^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B%2816%5Btex%5Dx%5E%7B2%7D "\frac{6}{(16[tex]x^{2}")
+ 8x +1} }[/tex]
d. f(x) =
= (4x - 5)^1/2
=
(4x - 5)^1/2 x 4
= (4x - 5)^-1/2 x 2
= 2(4x - 5)^-1/2
=
=![\frac{2}{[tex]\sqrt{(4x - 5)}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B%5Btex%5D%5Csqrt%7B%284x%20-%205%29%7D "\frac{2}{[tex]\sqrt{(4x - 5)}")
}[/tex]