Ba2+ + SO42- → BaSO4(s) ΔH = -30 kJ
(a) (b) (c)
ΔH = c – (a + b)
-30 = c – (540 – 910)
-30 = c -370
c = 340 (tidak ada jawaban di pilihan).
Setelah di cek di tabel ΔH, ternyata ΔH Ba2+(aq) = -540, bukan +540. Maka perhitungannya menjadi
-30 = c – (-540 – 910)
-30 = c + 1450
c = -1480
Semoga membantu
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Ba2+ + SO42- → BaSO4(s) ΔH = -30 kJ
(a) (b) (c)
ΔH = c – (a + b)
-30 = c – (540 – 910)
-30 = c -370
c = 340 (tidak ada jawaban di pilihan).
Setelah di cek di tabel ΔH, ternyata ΔH Ba2+(aq) = -540, bukan +540. Maka perhitungannya menjadi
ΔH = c – (a + b)
-30 = c – (-540 – 910)
-30 = c + 1450
c = -1480
Semoga membantu