Penjelasan dengan langkah-langkah:
[tex]misal : \\ panjang \: garis \: singgung \: persekutuan \\ dalam = ab \\ jarak \: kedua \: lingkaran = s[/tex]
[tex]diketahui : \\ ab = 36 \: cm \\ s = 39 \: cm \\ {r}^{1} = 11 \: cm[/tex]
[tex]ditanya : {r}^{2} = ...[/tex]
[tex]jawab : \\ {ab}^{2} = {s}^{2} - ( {r}^{1} + {r}^{2} ) {}^{2} \\ {36}^{2} = {39}^{2} - (11 + {r}^{2} ) {}^{2} \\ 1.296 = 1.521 - (11 + {r}^{2} ) {}^{2} \\ (11 + {r}^{2} ) = \sqrt{1.521 - 1.296} \\ 11 + {r}^{2} = \sqrt{225} \\ 11 + {r}^{2} = 15 \\ {r}^{2} = 15 - 11 \\ {r}^{2} = 4 \: cm[/tex]
[tex]jadi \: jari \: jari \: lingkaran \: ( {r}^{2} ) \: \\ adalah \: 4 \: cm[/tex]
#maaf kalau salah#
#semoga membantu#
#selamat berpuasa#
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Penjelasan dengan langkah-langkah:
[tex]misal : \\ panjang \: garis \: singgung \: persekutuan \\ dalam = ab \\ jarak \: kedua \: lingkaran = s[/tex]
[tex]diketahui : \\ ab = 36 \: cm \\ s = 39 \: cm \\ {r}^{1} = 11 \: cm[/tex]
[tex]ditanya : {r}^{2} = ...[/tex]
[tex]jawab : \\ {ab}^{2} = {s}^{2} - ( {r}^{1} + {r}^{2} ) {}^{2} \\ {36}^{2} = {39}^{2} - (11 + {r}^{2} ) {}^{2} \\ 1.296 = 1.521 - (11 + {r}^{2} ) {}^{2} \\ (11 + {r}^{2} ) = \sqrt{1.521 - 1.296} \\ 11 + {r}^{2} = \sqrt{225} \\ 11 + {r}^{2} = 15 \\ {r}^{2} = 15 - 11 \\ {r}^{2} = 4 \: cm[/tex]
[tex]jadi \: jari \: jari \: lingkaran \: ( {r}^{2} ) \: \\ adalah \: 4 \: cm[/tex]
#maaf kalau salah#
#semoga membantu#
#selamat berpuasa#